7x^2-50x-125=0

Solution for 7x^2-50x-125=0 equation:

7x^2-50x-125=0

a = 7; b = -50; c = -125;
Δ = b2-4ac
Δ = -502-4·7·(-125)
Δ = 6000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6000}=\sqrt{400*15}=\sqrt{400}*\sqrt{15}=20\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-20\sqrt{15}}{2*7}=\frac{50-20\sqrt{15}}{14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+20\sqrt{15}}{2*7}=\frac{50+20\sqrt{15}}{14}
$